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Mole fraction of a solute in an aqueous ...

Mole fraction of a solute in an aqueous solution is 0.2. The molality of the solution will be

A

`13.8`

B

`15.5`

C

`14.5`

D

`16.8`

Text Solution

Verified by Experts

The correct Answer is:
A
`x_(Lambda)=0.2`
`x_(H_(2))O = 1-0.2=0.8`
`"wt of" H_(2)O = 0.8xx18 = 14.4 g`
Molality
`=("moles of solute")/("wt. of solvent" (H_(2)O)"in kg")`
`= (2xx1000)/(14.4)=13.8`
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