`500 mL` of a glucose solution contains `6.02 xx 10^(22)` molecules. The concentration of the solution is :

Options

A. `0.1 M`
B. `1.0M`
C. `0.2M`
D. `2.0M`

Explanation

To find the concentration of the glucose solution, we will follow these steps:

### Step 1: Determine the number of moles of glucose
We know that 1 mole of any substance contains \(6.02 \times 10^{23}\) molecules (Avogadro's number). Given that the solution contains \(6.02 \times 10^{22}\) molecules of glucose, we can calculate the number of moles using the formula:

\[ \text{Number of moles} = \frac{\text{Number of molecules}}{\text{Avogadro's number}} \]

Substituting the values:

\[ \text{Number of moles} = \frac{6.02 \times 10^{22}}{6.02 \times 10^{23}} = 0.1 \text{ moles} \]

### Step 2: Convert volume from mL to L
The volume of the solution is given as \(500 \, \text{mL}\). To convert this to liters, we use the conversion factor \(1 \, \text{L} = 1000 \, \text{mL}\):

\[ \text{Volume in L} = \frac{500 \, \text{mL}}{1000} = 0.5 \, \text{L} \]

### Step 3: Calculate the concentration (molarity)
Molarity (concentration) is defined as the number of moles of solute per liter of solution. We can use the formula:

\[ \text{Molarity (M)} = \frac{\text{Number of moles}}{\text{Volume in L}} \]

Substituting the values we found:

\[ \text{Molarity} = \frac{0.1 \, \text{moles}}{0.5 \, \text{L}} = 0.2 \, \text{M} \]

### Final Answer
The concentration of the glucose solution is \(0.2 \, \text{M}\).

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