Home
Class 11
CHEMISTRY
14gm of element X combine with 16gm of o...

`14gm` of element `X` combine with `16gm` of oxygen. On the basis of this information, which of the following is the correct statement .

A

The element 'X' could have atomic weight of 7 and its's oxide the formula `XO`

B

The element 'X' could have atomic weight of 14 and its's oxide the formula `X_(2)O`

C

The element 'X' could have atomic weight of 7 and its's oxide the formula `X_(2)O`

D

The element 'X' could have atomic weight of 14 and its's oxide the formula `X_(2)O`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the information given about the element X and its combination with oxygen. ### Step 1: Determine the Molar Mass of Oxygen The atomic weight (molar mass) of oxygen is given as 16 g/mol. ### Step 2: Determine the Molar Mass of Element X We know that 14 g of element X combines with 16 g of oxygen. We can use this information to find the possible molar masses of element X. ### Step 3: Calculate the Moles of Oxygen Using the molar mass of oxygen: \[ \text{Moles of Oxygen} = \frac{\text{mass of oxygen}}{\text{molar mass of oxygen}} = \frac{16 \text{ g}}{16 \text{ g/mol}} = 1 \text{ mol} \] ### Step 4: Analyze the Moles of Element X Now, we need to find out how many moles of element X are present in 14 g. We can assume two possible atomic weights for element X: 7 g/mol and 14 g/mol. 1. **If the atomic weight of X is 14 g/mol:** \[ \text{Moles of X} = \frac{14 \text{ g}}{14 \text{ g/mol}} = 1 \text{ mol} \] The formula of the oxide would be XO. 2. **If the atomic weight of X is 7 g/mol:** \[ \text{Moles of X} = \frac{14 \text{ g}}{7 \text{ g/mol}} = 2 \text{ mol} \] The formula of the oxide would be X₂O. ### Step 5: Conclusion Based on the calculations: - If the atomic weight of X is 14 g/mol, the formula is XO. - If the atomic weight of X is 7 g/mol, the formula is X₂O. Thus, both atomic weights are possible based on the given information. However, the question asks for the correct statement based on the combination of X and oxygen. ### Final Answer The correct statement is that element X can have an atomic weight of either 7 g/mol or 14 g/mol, leading to the formation of either XO or X₂O. ---
Promotional Banner

Topper's Solved these Questions

  • MOLE CONCEPT

    ALLEN|Exercise EXERCISE - 02|46 Videos
  • MOLE CONCEPT

    ALLEN|Exercise EXERCISE -03|13 Videos
  • MOLE CONCEPT

    ALLEN|Exercise Exercise - 05(B)|8 Videos
  • IUPAC NOMENCLATURE

    ALLEN|Exercise Exercise - 05(B)|7 Videos
  • QUANTUM NUMBER & PERIODIC TABLE

    ALLEN|Exercise J-ADVANCED EXERCISE|24 Videos

Similar Questions

Explore conceptually related problems

Which of the following is correct combination ?

On the basis of Lewis concept, which of the following are correct?

Which of the following combinations is correct ?

Which of the following combination is correct ?

Which of the following combination is correct?

Which of the following combination is correct?

Which of the following combination is correct:

Which of the following combination is correct:

Which of the following combinations is correct?

Which of the following is CORRECT combination?

ALLEN-MOLE CONCEPT-EXERCISE - 01
  1. The molarity of the solution containing 2.8% (mass/volume) solution of...

    Text Solution

    |

  2. The molality of a sulphuric acid solution is 0.2"mol"//"kg" Calculate ...

    Text Solution

    |

  3. What volume of a 0.8M solution contains 100 millimoles of the solute .

    Text Solution

    |

  4. 500 mL of a glucose solution contains 6.02 xx 10^(22) molecules. The c...

    Text Solution

    |

  5. 50mL of CO is mixed with 20mL of oxygen and sparked. After the reactio...

    Text Solution

    |

  6. 14gm of element X combine with 16gm of oxygen. On the basis of this in...

    Text Solution

    |

  7. 1.5gm mixture of SiO(2) and Fe(2)O(3) on very strong heating leave a r...

    Text Solution

    |

  8. Aspartame an artificial sweetener contains 9.52 "wt". % nitrogen. Ther...

    Text Solution

    |

  9. The total number of neutrons present in 10g D(2)O (D "is" 2 H are .

    Text Solution

    |

  10. The % of Fe^(+2) in Fe(0.93)O(1.00) is .

    Text Solution

    |

  11. The mass precent of oxYgen in 109% oleum is .

    Text Solution

    |

  12. A definite amount of gaseous hydrocarbon having ("carbon atoms less t...

    Text Solution

    |

  13. C(6)H(5)OH(g)+O(2)rarrCO(2)(g) +H(2)O(l) Magnitude of volume change ...

    Text Solution

    |

  14. 10ml of compound containing 'N' and 'O' is mixed with 30ml of H(2) to ...

    Text Solution

    |

  15. 200ml of a gaseous mixture containing CO,CO(2) and N(2) on complete co...

    Text Solution

    |

  16. When 20ml of mixture of O(2) and O(3) is heated the volume becomes 29m...

    Text Solution

    |

  17. A mixture of C(2)H(2) and C(3)H(8) occupied a certain volume at 80mm H...

    Text Solution

    |

  18. 20 Ml of a mixture of CO and H(2) were mixed with excess of O(2) and e...

    Text Solution

    |

  19. The % by volume of C(4)H(10) in a gaseous mixture of C(4)H(10) and CO ...

    Text Solution

    |

  20. An ideal gaseous mixture of ethane (C(2)H(6)) and ethane (C(2)H(4)) oc...

    Text Solution

    |