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A definite amount of gaseous hydrocarbon...

A definite amount of gaseous hydrocarbon having `("carbon atoms less than" 5)` was burnt with sufficient amount of `O_(2)`. The volume of all reactants was `600mL`. After the explosion the volume of the product `[CO_(2)(g)` and `H_(2)O (g)]` was found to be `700 mL` under the similar conditions. The molecular formula of the compound is ?

A

`C_(3)H_(8)`

B

`C_(3)H_(6)`

C

`C_(3)H_(4)`

D

`C_(4)H_(10)`

Text Solution

Verified by Experts

The correct Answer is:
A
Mass `%` of `O=((60/(98)xx4xx16+(40)/(80)xx3xx16)xx100)/(100) = 63.18%`
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