In the preceding problem, if the compound contains `12.8%` nitrogen and `9.8%` sulphur how many nitrogen and sulphur atoms are present per atomof sodium?

Options

A. `2` and `1`
B. `1` and `3`
C. `1` and `2`
D. `3` and `1`

Explanation

To solve the problem, we need to determine how many nitrogen and sulfur atoms are present per atom of sodium in the compound. We know the percentages of nitrogen and sulfur in the compound and the molecular weight of the compound.

### Step-by-Step Solution:

1. **Determine the mass of nitrogen and sulfur in 329 g of the compound**:
- The compound contains 12.8% nitrogen.
- The mass of nitrogen in 329 g of the compound:
\[ \text{Mass of Nitrogen} = \frac{12.8}{100} \times 329 = 42.112 \text{ g} \]
- The compound contains 9.8% sulfur.
- The mass of sulfur in 329 g of the compound:
\[ \text{Mass of Sulfur} = \frac{9.8}{100} \times 329 = 32.262 \text{ g} \]

2. **Calculate the number of moles of nitrogen and sulfur**:
- The atomic mass of nitrogen (N) is 14 g/mol.
- The number of moles of nitrogen:
\[ \text{Moles of Nitrogen} = \frac{42.112 \text{ g}}{14 \text{ g/mol}} = 3.007 \text{ moles} \]
- The atomic mass of sulfur (S) is 32 g/mol.
- The number of moles of sulfur:
\[ \text{Moles of Sulfur} = \frac{32.262 \text{ g}}{32 \text{ g/mol}} = 1.007 \text{ moles} \]

3. **Determine the ratio of nitrogen and sulfur atoms to sodium atoms**:
- Since the compound contains 1 mole of sodium, the number of nitrogen atoms per atom of sodium is approximately 3, and the number of sulfur atoms per atom of sodium is approximately 1.
- Therefore, we can conclude:
- Nitrogen atoms per atom of sodium = 3
- Sulfur atoms per atom of sodium = 1

### Final Answer:
The compound contains **3 nitrogen atoms** and **1 sulfur atom** per atom of sodium.

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