How many `g` of element are present in `35,125 g` atom of `Si`. `("Given at". `wt` "of" Si = 28.)`

Explanation

To solve the question, "How many grams of element are present in 35.125 g atom of Si (Silicon)?" we will follow these steps:

### Step-by-Step Solution:

1. **Understand the Given Information**:
- We are given the weight of Silicon (Si) in grams, which is 35.125 g.
- The atomic weight (molar mass) of Silicon (Si) is given as 28 g/mol.

2. **Calculate the Number of Moles**:
- The number of moles can be calculated using the formula:
\[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \]
- Substituting the given values:
\[ \text{Number of moles} = \frac{35.125 \text{ g}}{28 \text{ g/mol}} = 1.2544642857142857 \text{ moles} \]

3. **Calculate the Mass of Silicon**:
- To find the mass of Silicon in grams, we can use the formula:
\[ \text{Mass} = \text{Number of moles} \times \text{Molar mass} \]
- Substituting the values:
\[ \text{Mass} = 1.2544642857142857 \text{ moles} \times 28 \text{ g/mol} = 35.125 \text{ g} \]

4. **Final Answer**:
- The mass of Silicon present in 35.125 g atom of Si is 35.125 g.

### Summary:
The amount of Silicon present in 35.125 g atom of Si is 35.125 g.