Density of a gas relative t air is `1.17`. Find the mol. Mass of the gas `[M_(air)=29g//mol]`

Explanation

To find the molar mass of the gas given its density relative to air, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Given Information**:
- The density of the gas relative to air is given as \(1.17\).
- The molar mass of air (\(M_{air}\)) is given as \(29 \, \text{g/mol}\).

2. **Set Up the Ratio**:
- The relationship between the molar mass of the gas (\(M_{gas}\)) and the molar mass of air can be expressed as:
\[ \frac{M_{gas}}{M_{air}} = \text{Relative Density} \]
- Substituting the known values, we have:
\[ \frac{M_{gas}}{29 \, \text{g/mol}} = 1.17 \]

3. **Solve for Molar Mass of the Gas**:
- To find \(M_{gas}\), we can rearrange the equation:
\[ M_{gas} = 1.17 \times M_{air} \]
- Now substitute \(M_{air} = 29 \, \text{g/mol}\):
\[ M_{gas} = 1.17 \times 29 \, \text{g/mol} \]

4. **Calculate the Molar Mass**:
- Performing the multiplication:
\[ M_{gas} = 1.17 \times 29 = 33.93 \, \text{g/mol} \]

5. **Conclusion**:
- The molar mass of the gas is \(33.93 \, \text{g/mol}\).

### Final Answer:
The molar mass of the gas is \(33.93 \, \text{g/mol}\).

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