`10 g` of a sample of a mixture of `CaCl_(2)` and `NaCl` is treated to precipitate all the calcium as `CaCO_(3)`. This `CaCO_(3)` is heated to convert all the `Ca` to `CaO` and the final mass of `CaO` is 1.62 g.The percent by mass of `CaCl_(2)` in the origial mixture is

Answer

`67.9%`

Explanation

`n_(CaCl_(2))=n_(caO)=(1.62)/(56)=0.02892`
`m_(CaCl_(2))=0.02892xx111=3.211g`
`m_(NaCl)=6.7889gm`
`%NaCl=67.9%`