Nitric acid canbe produced from `NH_(3)`in three steps process given below
(I)`4NH_(3)(g)+5O_(2)(g)to4NO(g)+6H_(2)O(g)`
(II)`2NO(g)+O_(2)(g)to 2NO_(3)(g)`
`3NO_(2)(g)+H_(2)O(l)to 2HNO_(3)(aq)+NO(g)`
percent yield of `1^(st)` ,`2^(nd)` and `3^(rd)` steps are respectively 50%,60% and 80% respectivley then what volume of `NH_(3)`(g) at 1 atm and `0^(@)`required to produced1575 g of `HNO_(3)` .

Answer

`1811.5kg`

Explanation

`(1260xx1000)/(63) = (W_(NH_(3)))/(7) xx (4)/(4) xx (2)/(2) xx (2)/(3)`
`W_(NH_(3))=1811.5 kg`