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The amount of arsenic pentasulphide that...

The amount of arsenic pentasulphide that can be obtained when 35.5 g arsenic acid is treated with excess `H_(2)S` in the presence of conc. HCl (assuming 100% conversion) is : (Atomic mass of As = 75u)
`2H_(3)AsO_(4) rarr 5H_(2)S rarr As_(2)S_(5) + 8H_(2)O`

A

`0.25` mol

B

`0.50` mol

C

`0.125` mol

D

`0.333` mol

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The correct Answer is:
C
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