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The position of some metals in the elect...

The position of some metals in the electrochemical series in dectreasing electropositeve character is given as ` Mg gt Al gt Zn gt Cu gt Ag`. What will happen if a copper spoon is used to stir a solution of aluminimum nitrate ?

A

The spoon will get coated with aluminium

B

An alloy of aluminium and copper nitrate

C

The solution becomes blue

D

There is no reaction

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The correct Answer is:
To solve the problem, we will analyze the electrochemical series and the potential reactions between copper and aluminum nitrate. ### Step-by-Step Solution: 1. **Understanding the Electrochemical Series**: The electrochemical series ranks metals based on their electropositive character, which is related to their standard reduction potentials (SRP). The series provided is: \[ \text{Mg} > \text{Al} > \text{Zn} > \text{Cu} > \text{Ag} \] This means that magnesium is the most electropositive (most likely to lose electrons) and silver is the least. **Hint**: Remember that a metal with a lower SRP can displace a metal with a higher SRP from its salt solution. 2. **Identifying the Metals in the Reaction**: We are considering a copper spoon (Cu) and a solution of aluminum nitrate (Al(NO₃)₃). In this case, we need to determine if copper can displace aluminum from its nitrate solution. 3. **Analyzing the Reaction**: The potential reaction can be represented as: \[ \text{Cu} + \text{Al(NO}_3\text{)}_3 \rightarrow \text{Cu(NO}_3\text{)}_2 + \text{Al} \] In this reaction, copper is being oxidized (losing electrons), and aluminum is being reduced (gaining electrons). 4. **Comparing Standard Reduction Potentials**: From the electrochemical series: - Aluminum (Al) has a higher electropositive character than copper (Cu), meaning it has a lower SRP. - Therefore, aluminum is more likely to remain in its ionic form rather than being displaced by copper. 5. **Conclusion**: Since copper cannot displace aluminum from aluminum nitrate due to its higher reduction potential, no reaction will occur. Thus, the correct answer is: \[ \text{Option D: There is no reaction.} \] ### Summary: Using a copper spoon to stir a solution of aluminum nitrate will result in no reaction because copper cannot displace aluminum from its nitrate solution due to the relative positions of the metals in the electrochemical series.

To solve the problem, we will analyze the electrochemical series and the potential reactions between copper and aluminum nitrate. ### Step-by-Step Solution: 1. **Understanding the Electrochemical Series**: The electrochemical series ranks metals based on their electropositive character, which is related to their standard reduction potentials (SRP). The series provided is: \[ \text{Mg} > \text{Al} > \text{Zn} > \text{Cu} > \text{Ag} ...
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ALLEN-ELECTROCHEMISTRY-Part (II) EXERCISE-01
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  2. The emf of the cell, Ni|Ni^(2+)(1.0M)||Ag^(+)(1.0M)|Ag [E^(@) for Ni^(...

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  3. The position of some metals in the electrochemical series in dectreasi...

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  18. Zn|Zn((C(1)))^(2+)||Zn((C(2)))^(2+)| Zn(s). Then DeltaG is -ve if

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