Using the information in the preceding p...

Using the information in the preceding problem, calculate the solubility product of `AgI` in water at `25^(@)C [E_((Ag +Ag)^(@) = +0.799volt]`:-

`1.97 xx 10^(-17)`

`7.91 xx 10^(-17)`

`1.79 xx 10^(-17)`

`9.17 xx 10^(-17)`

Text Solution

Verified by Experts

The correct Answer is:

`AgI+e^(-)rarr Ag+ I^(-) E^(@)= -0.151`
`{:(E^(@)=-0.95 ,,,E=E^(@)-(0.0551)/(1)log K_(sp)),(-16.074=log_(10)K_(sp),,,10^(-16.074)=K_(sp)):}`
`7.91xx10^(-17)=K_(sp)`

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