`{:(Column-I,Column-II),((A)"Cathode",(p)"Primary cell"),((B)1"Coulomb",(q)"Secondary cell"),((C)"Dry cell",(r)6.24 xx 10^(18) "electrons"),((D)"Lead stron cell",(s)"Concentration cell"),((E)Zn|Zn^(2+)(0.10M)||Zn^(2+)(0.1M)|Zn,(u)"Positive terminal of electrochemical cell"):}`

Answer

To solve the matching question between Column I and Column II, we will analyze each item in Column I and find the corresponding item in Column II.

### Step-by-Step Solution:

1. **Match "Cathode" (A)**:
- The cathode is the electrode where reduction occurs. In an electrochemical cell, the cathode is the positive terminal.
- **Match**: A → u (Positive terminal of electrochemical cell).

2. **Match "1 Coulomb" (B)**:
- 1 Coulomb of charge is equivalent to the charge of approximately \(6.24 \times 10^{18}\) electrons. This can be derived from the relationship between charge and the number of electrons.
- **Match**: B → r (6.24 x 10^18 electrons).

3. **Match "Dry Cell" (C)**:
- A dry cell is a type of electrochemical cell that is classified as a primary cell. Primary cells are designed for single-use and cannot be recharged.
- **Match**: C → p (Primary cell).

4. **Match "Lead Storage Cell" (D)**:
- A lead storage cell, commonly known as a lead-acid battery, is a type of secondary cell. Secondary cells can be recharged and used multiple times.
- **Match**: D → q (Secondary cell).

5. **Match "Zn|Zn²⁺(0.10M)||Zn²⁺(0.1M)|Zn" (E)**:
- This notation represents a concentration cell, where the concentration of Zn²⁺ ions differs on either side of the cell.
- **Match**: E → s (Concentration cell).

### Final Matches:
- A → u (Cathode → Positive terminal of electrochemical cell)
- B → r (1 Coulomb → 6.24 x 10^18 electrons)
- C → p (Dry cell → Primary cell)
- D → q (Lead storage cell → Secondary cell)
- E → s (Zn|Zn²⁺(0.10M)||Zn²⁺(0.1M)|Zn → Concentration cell)