Home
Class 12
CHEMISTRY
Statement-I: In the Daniel cell, if conc...

Statement-I: In the Daniel cell, if concentration of `Cu^(2+)` and `Zn^(2+)` ions are doubled the emf of the cell will not change.
Because Statement-II: If the concentration of ions in contact with the metals is doubled, the electrode potential is doubled.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the statements about the Daniel cell, we will analyze each statement step by step. ### Step-by-Step Solution: 1. **Understanding the Daniel Cell**: The Daniel cell consists of two half-cells: one with zinc (Zn) and the other with copper (Cu). The cell operates based on the redox reactions of these metals and their respective ions in solution. 2. **Statement-I Analysis**: - **Statement**: In the Daniel cell, if the concentration of `Cu^(2+)` and `Zn^(2+)` ions are doubled, the emf of the cell will not change. - **Explanation**: The electromotive force (emf) of the cell is determined by the Nernst equation, which states that the emf is proportional to the logarithm of the ratio of the concentrations of the ions involved in the half-reactions. - The Nernst equation for the Daniel cell can be expressed as: \[ E = E^\circ - \frac{RT}{nF} \ln \left( \frac{[Cu^{2+}]}{[Zn^{2+}]} \right) \] - If both concentrations are doubled, the ratio \(\frac{[Cu^{2+}]}{[Zn^{2+}]}\) remains the same (2/2 = 1). Therefore, the logarithmic term does not change, and thus the emf remains constant. 3. **Conclusion for Statement-I**: - **Result**: Statement-I is **incorrect** because the emf does not change when both concentrations are doubled. 4. **Statement-II Analysis**: - **Statement**: If the concentration of ions in contact with the metals is doubled, the electrode potential is doubled. - **Explanation**: The electrode potential is directly proportional to the concentration of the ions in contact with the electrode, as described by the Nernst equation. - If the concentration of \(Cu^{2+}\) ions is doubled, the electrode potential for the copper half-cell will increase, and similarly for the zinc half-cell. However, the potential does not double; it increases logarithmically based on the concentration change. 5. **Conclusion for Statement-II**: - **Result**: Statement-II is **incorrect** because while the potential increases with concentration, it does not double; it follows a logarithmic relationship. ### Final Conclusion: - Statement-I is **incorrect**. - Statement-II is **incorrect**.
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    ALLEN|Exercise EXERCISE-04 [A]|55 Videos
  • ELECTROCHEMISTRY

    ALLEN|Exercise EXERCISE-04 [B]|23 Videos
  • ELECTROCHEMISTRY

    ALLEN|Exercise EXERCISE-02|35 Videos
  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise ORGANIC CHEMISTRY|472 Videos
  • HYDROCARBON

    ALLEN|Exercise MCQ|15 Videos

Similar Questions

Explore conceptually related problems

Assertion (A) : In a Daniell cell, if the concentration of Cu^(2+) and Zn^(2+) ions are doubled, the EMF of the cell will be doubled. Reason (R) : If the concentration of ions in contact with metals is doubled, the electrode potential is doubled. (a)If both (A) and (R) are correct, and (R) is the correct explanation of (A) . (b)If both (A) and (R) are correct, but (R) is not the correct explanation of (A) . (c)If (A) is correct, but (R) is incorrect. (d)If (A) is incorrect, (R) is correct.

Consider the cell Zn|Zn^(2+) || Cu^(2+)|Cu. If the concentration of Zn and Cu ions are doubled, the emf of the cell.

In the reaction 2A + B to A_2B , if the concentration of A is doubled and of B is halved, then the rate of the reaction will:

A cell contains two hydrogen electrodes. The negative electrode is in contact with a solution of 10^(-6)M hydrogen ions. The EMF of the cell is 0.118V at 25^(@)C . Calculate the concentration of hydrogen ions at the positive electrode.

Consider a reaction, 2A + B rarr Products When concentration of B alone was doubled, the half-life did not change. When the concentration of A alone was doubled, the rate increased by two times. The unit of rate constant for this reaction is :

How many times will the rate of the elementary reaction 3X + Y → X2Y change if the concentration of the substance X is doubled and that of Y is halved?

The standard electrode potential of Cu|Cu^(+2) is - 0.34 Volt. At what concentration of Cu^(+2) ions, will this electrode potential be zero?

Consider figure from the above question and answer the questions (i) to (vi) given below. (i) Redraw the diagram to show the direction of electron flow. (ii) Is silver plate the anode or cathode? (iii) what will happen it salt bridge is removed? (iv) When will the cell stop functining? ( v) How will concentration of Zn^(2+) ions and Ag^(+) ions be affected when the cell function? (vi) How will the concentration of Zn^(2+) ions and Ag^(+) ions be affected after the cell becomes dead?

The rate of reaction, 2NO + Cl_2 to 2NOCI is doubled when concentration of Cl_2 is doubled and it becomes 8 times when concentrations of both NO and Cl_2 are doubled. Deduce the order of this reaction.

ALLEN-ELECTROCHEMISTRY-EXERCISE-03
  1. Statement-I: In electrolysis the quantity needed for depositing 1 mole...

    Text Solution

    |

  2. Statement-I: Equivalent conductance of all electrolytes decreases with...

    Text Solution

    |

  3. Statement-I: If an aqueous solution of NaCI is electrolysed, the produ...

    Text Solution

    |

  4. Statement-I: Molar conductivity of a weak electrolyte at infinite dilu...

    Text Solution

    |

  5. Statement-I: Gold chloride (AuCI(3)) solution cannot be stored in a ve...

    Text Solution

    |

  6. Statement-I: In the Daniel cell, if concentration of Cu^(2+) and Zn^(2...

    Text Solution

    |

  7. STATEMENT 1 H(2)+O(2) fuel cel gives a constant voltage throughout its...

    Text Solution

    |

  8. A: Block of magnesium are often stapped to steel hulls of ocean going ...

    Text Solution

    |

  9. Statement-I: Absolute value of E(red)^(0) of an electrode cannot be de...

    Text Solution

    |

  10. Copper reduced NO(3)^(-) into NO and NO(2) depending upon conc.of HNO(...

    Text Solution

    |

  11. Copper reduced NO(3)^(-) into NO and NO(2) depending upon conc.of HNO(...

    Text Solution

    |

  12. Accidentally chewing on a stray fragmet of aluminium foil can causes a...

    Text Solution

    |

  13. Accidentally chewing on a stray fragmet of aluminium foil can causes a...

    Text Solution

    |

  14. Accidentally chewing on a stray fragmet of aluminium foil can causes a...

    Text Solution

    |

  15. A sample of water from a large swimming pool has a resistance of 10000...

    Text Solution

    |

  16. A sample of water from a large swimming pool has a resistance of 10000...

    Text Solution

    |

  17. A sample of water from a large swimming pool has a resistance of 10000...

    Text Solution

    |

  18. A half cell is prepared by K(2)Cr(2)O(7) in a buffer solution of pH =1...

    Text Solution

    |

  19. A half cell is prepared by K(2)Cr(2)O(7) in a buffer solution of pH =1...

    Text Solution

    |

  20. A half cell is prepared by K(2)Cr(2)O(7) in a buffer solution of pH =1...

    Text Solution

    |