The specific conductance of a `N//10 KCI` solution at `18^(@)C` is `1.12 xx 10^(-2) mho cm^(-1)`. The resistance of the solution contained in the cell is found to be 65 ohms. Calculate the cell constant.

Explanation

To calculate the cell constant for the given KCl solution, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the given values**:
- Specific conductance (κ) = \(1.12 \times 10^{-2} \, \text{mho cm}^{-1}\)
- Resistance (R) = \(65 \, \Omega\)

2. **Understand the relationship between specific conductance, resistance, and cell constant**:
The relationship is given by the formula:
\[ \kappa = \frac{G^*}{R} \]
where \(G^*\) is the cell constant.

3. **Rearrange the formula to find the cell constant**:
From the relationship, we can rearrange it to find \(G^*\):
\[ G^* = \kappa \times R \]

4. **Substitute the known values into the equation**:
Now, substituting the values of κ and R into the equation:
\[ G^* = (1.12 \times 10^{-2} \, \text{mho cm}^{-1}) \times (65 \, \Omega) \]

5. **Perform the multiplication**:
\[ G^* = 1.12 \times 65 \times 10^{-2} \]
\[ G^* = 72.8 \times 10^{-2} \, \text{cm}^{-1} \]

6. **Convert to standard form**:
\[ G^* = 0.728 \, \text{cm}^{-1} \]

### Final Answer:
The cell constant \(G^*\) is \(0.728 \, \text{cm}^{-1}\).

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