Specific conductance of pure water at `25^(@)C` is `0.58 xx 10^(-7)` mho `cm^(-1)`. Calculate ionic product of wter `(K_(w))` if ionic conductances of `H^(+)` and `OH^(-)`ions at infinite are `350` and `198` mho `cm^(2)` respectively at `25^(@)C`

Answer

`1 xx 10^(-14) ("mole"//"litre")^(2)`

Explanation

`K_(W)=[H^(+)][OH^(-)]`
`K_(W)=S^(2)`
`lamda^(infty)=(K xx 1000)/(S)`
`S~~ 1 xx 10^(-7)`
`K_(W) ~~(1 xx 10^(-7))^(2)=1 xx 10^(-14)`.