The e.m.f. of the cell obtained by combining `Zn` and `Cu` electrode of a Daniel cell with N calomel electrode in two different arrangements are `1.083V` and `0.018V` respectively at `25^(@)C`. If the standard reduction potential of N calomel electrode is `0.28V` find the emf of Daniel cell.

Explanation

To find the EMF of the Daniel cell using the given data, we can follow these steps:

### Step 1: Understand the Cell Configurations
We have two arrangements of the Daniel cell with a N calomel electrode. The EMF values for these arrangements are given as:
- Arrangement 1 (Zn | N calomel): EMF = 1.083 V
- Arrangement 2 (Cu | N calomel): EMF = 0.018 V

### Step 2: Use the Standard Reduction Potential of N Calomel Electrode
The standard reduction potential of the N calomel electrode is given as:
- E°(N calomel) = 0.28 V

### Step 3: Calculate the Oxidation Potential of Zinc Electrode
For the first arrangement (Zn | N calomel), we can write the equation for the cell EMF:
\[ E_{cell} = E_{Zn}^{ox} + E_{N calomel}^{red} \]
Where:
- \( E_{Zn}^{ox} \) is the oxidation potential of the zinc electrode.
- \( E_{N calomel}^{red} = 0.28 \, V \)

From the given EMF:
\[ 1.083 = E_{Zn}^{ox} + 0.28 \]
Rearranging gives:
\[ E_{Zn}^{ox} = 1.083 - 0.28 = 0.803 \, V \]

### Step 4: Calculate the Oxidation Potential of Copper Electrode
For the second arrangement (Cu | N calomel), we can write the equation for the cell EMF:
\[ E_{cell} = E_{Cu}^{ox} + E_{N calomel}^{red} \]
Where:
- \( E_{Cu}^{ox} \) is the oxidation potential of the copper electrode.

From the given EMF:
\[ 0.018 = E_{Cu}^{ox} + 0.28 \]
Rearranging gives:
\[ E_{Cu}^{ox} = 0.018 - 0.28 = -0.262 \, V \]

### Step 5: Calculate the Reduction Potential of Copper
The reduction potential of copper can be calculated as:
\[ E_{Cu}^{red} = -E_{Cu}^{ox} = -(-0.262) = 0.262 \, V \]

### Step 6: Calculate the EMF of the Daniel Cell
The EMF of the Daniel cell can be calculated using the oxidation potential of zinc and the reduction potential of copper:
\[ E_{Daniel} = E_{Zn}^{ox} + E_{Cu}^{red} \]
Substituting the values:
\[ E_{Daniel} = 0.803 + 0.262 = 1.065 \, V \]

### Final Answer
The EMF of the Daniel cell is **1.065 V**.

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