An external current source giving a current of `5.0A` was joined with Daniel cell arrangement opposing the normal current flow and was removed after 10 hrs. Before passing the current the LHE and RHE contained 1L each of `1M Zn^(2+)` and `Cu^(2+)` respectively. Find the EMF supplied by the Daniel cell after removal of teh external curretn source, `E^(@)` of `Zn^(2+)//Zn` and `Cu^(2+)//Cu` at `25^(@)C` is `-0.76` and `+0.34V` respectively.

Answer

`1.143V`

Explanation

`n_(E) = (5 xx 3600 xx 10)/(96500)`
`n_(E) = 1.865`
`Zn^(2+) rarr ZN +2e^(-)`
mole of `Zn^(2+)` deposited `= 0.932`
mole of `Zn^(2+)` left `= 1 - 0.932`
`=0.0673`
`Cu rarr Cu^(2+) +2e^(-)`
mole of `Cu^(2+)` produced `=0.932`
so total mole of `Cu^(2+) = 1.932`
`E_(cell) = E^(@) -(0.059)/(2)log.(0.0673)/(1.932)`
`E_(cell) = 1.143V`