A satellite moves estwards very near the surface of the Earth in equitorial plane with speed `(v_(0))`. Another satellite moves at the same height with the same speed in the equatorial plane but westwards. If `R` =radius of the Earth and `omega` be its angular speed of the Earth about its own axis. Then find the approximate difference in the two time period as observed on the earth.

Explanation

To solve the problem, we need to find the difference in the time periods of two satellites moving in opposite directions (one eastward and the other westward) at the same height near the Earth's surface. Let's denote:

- \( R \) = radius of the Earth
- \( \omega \) = angular speed of the Earth
- \( v_0 \) = speed of the satellites

### Step 1: Understand the Time Period Formula
The time period \( T \) of an object moving in a circular path is given by the formula:
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