Two particles of equal mass (m) each move in a circle of radius (r) under the action of their mutual gravitational attraction find the speed of each particle.

Options

A. `(1)/(2R)sqrt((1)/(Gm))`
B. `sqrt((Gm)/(2R))`
C. `(1)/(2)sqrt((Gm)/(R))`
D. `sqrt((4Gm)/(R))`

Answer

C

Explanation

Centripetal force provided by the gravitaional force of attraction
Between two particles i.e., `(mv^(2))/(R)=(Gmxxm)/((2R)^(2))impliesv=(1)/(2)sqrt((Gm)/(R))`