Home
Class 12
PHYSICS
If the law of gravitation be such that t...


If the law of gravitation be such that the force of attraction between two particles vary inversely as the `5//2^(th)` powr of their separation then the graph of orbital velocity `v_(0)` plotted against the distance `r` of a satellite from the earth's centre on a log-log scale is shown alongside the slope oline will be

A

`-(5)/(4)`

B

`-(5)/(2)`

C

`-(3)/(4)`

D

`-1`

Text Solution

Verified by Experts

The correct Answer is:
C

`(mv_(0)^(2))/(r)=(GMm)/(r^(5//2))impliesv_(0)=(sqrt(GM))/(r^(3//4))implieslnv_(0)=lnsqrt(GM)-(3)/(4)lnr`
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    ALLEN|Exercise Exercise 1 (Check your Grasp)|28 Videos
  • GRAVITATION

    ALLEN|Exercise Exercise 2 (Brain Teasers)|27 Videos
  • GEOMETRICAL OPTICS

    ALLEN|Exercise subjective|14 Videos
  • KINEMATICS-2D

    ALLEN|Exercise Exercise (O-2)|46 Videos

Similar Questions

Explore conceptually related problems

The energy density u is plotted against the distance r from the centre of a spherical charge distribution on a log-log scale. Find the magnitude of slope of obtained straight line.

Suppose the gravitational attraction varies inversely as the distance from the earth. The orbital velocity of a satellite in such a case varies as nth power of distance where n is equal to

If the gravitational force had varied as r^(-5//2) instead of r^(-2) the potential energy of a particle at a distance 'r' from the centre of the earth would be proportional to

The gravitational force between two objects is proportional to 1//R (and not as 1//R^(2) ) where R is separation between them, then a particle in circular orbit under such a force would have its orbital speed v proportional to

The gravitational force between two objects is proportional to 1//R (and not as 1//R^(2) ) where R is separation between them, then a particle in circular orbit under such a force would have its orbital speed v proportional to

Two particles of masses m and 3m are moving under their mutual gravitational force, around their centre of mass, in circular orbits. The separation between the masses is r. The gravitational attraction the two provides nessary centripetal force for circular motion The ratio of centripetal forces acting on the two masses will be

At t = 0 , the positions and velocities of two particles are as shown in the figure. They are kept on a smooth surface and being mutually attracted by gravitational force. Find the position of centre of mass at t = 2s . .

At t = 0 , the positions and velocities of two particles are as shown in the figure. They are kept on a smooth surface and being mutually attracted by gravitational force. Find the position of centre of mass at t = 2s . .

A solid sphere of uniform density and radius R applies a gravitational force of attraction equal to F_(1) on a particle placed at P , distance 2R from the centre O of the sphere. A spherical cavity of radius R//2 is now made in the sphere as shown in figure. The particle with cavity now applies a gravitational force F_(2) on same particle placed at P . The radio F_(2)//F_(1) will be

Two charged particle A and B repel each other by a force k/r^2 where is a constant and r is th separation between them. The particle A is clamped to a fixed point in the lab and the particle B which has a mass m, is released from rest with asn initial separartion r_0 form A. Find the change in the potential energyof hte wo particle system as the separation increases to a large value. What will be the speed o the particle b in this situation?