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Weight of a body of mass m decreases by ...

Weight of a body of mass m decreases by `1%` when it is raised to height h above the earth's surface. If the body is taken on depth h in a mine, change in its weight is

A

decrease by 0.5%

B

decrease by 2%

C

increase by 0.5%

D

increase by 1%

Text Solution

Verified by Experts

The correct Answer is:
A

`g'=g(1-(2h)/(R)),(Deltag)/(g)=(2h)/(R)`
`1=2(h)/(R)implies(h)/(R)=(1)/(2),g'=g(1-(d)/(R))`
`(Deltag')/(g)=(d)/(R)implies(h)/(R)g` decreases by 0.5%
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