If g be the acceleration due to gravity of the earth's surface, the gain is the potential energy of an object of mass m raised from the surface of the earth to a height equal to the radius R of the earth is

Options

A. `(mgR)/(2)`
B. 2mgR
C. mgR
D. `(mgR)/(4)`

Answer

A

Explanation

`PE_(i)=-(GM_(e)m)/(R)=-mgR,PE_(f)=-(GM_(e)m)/(2R)=-(mgR)/(2)`
Increase in PE is `(mgR)/(2)`