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A narrow monochromatic beam of light of intensity `I` is incident on a glass plate as shown in figure. Another identical glass plate is kept close to the first one `&` parallel to it. Each glass plate reflects `25%` of the light incident on it `&` transmits the remaining. The ratio of the minimum `&` the maximum intensities in the interference pattern formed by the two beams obtained after one reflection at each plate is `1:n` find value of `n.`

Text Solution

Verified by Experts

The correct Answer is:
`1:49`

Each plate reflects 25% and transmits `75^(@)` incident beam has an intensity I. this beam undergoes multiple reflections and refractions. The corresponding intensity after each reflection and refraction (transmission) are shown in figure.
Interference pattern is to take place between rays 1 and 2. `I_(1)=I//4` and `I_(2)=9I//64`
`therefore(I_(min))/(I_(max))=((sqrt(I_(1))-sqrt(I_(2)))/(sqrt(I_(1))+sqrt(I_(2))))^(2)=(1)/(49)`
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