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The maximum numbers of possible interfer...

The maximum numbers of possible interference maxima for slit separation equal to twice the wavelength in Young's double slit experiment is

A

infinite

B

five

C

three

D

zero

Text Solution

Verified by Experts

The correct Answer is:
B

`dsintheta=nlamdaimpliesn=(dsintheta)/(lamda)=(2lamdasintheta)/(lamda)=2sintheta`
`impliesn_(max)=2`
`implies` Maximum number of possible Interference maxima `=(2n_(max)+1)=5`
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ALLEN-WAVE OPTICS-Exercise 5 A (Previous Years Questions)
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  2. The maximum numbers of possible interference maxima for slit separatio...

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