Two flask A and B of equal capacity contains `CO_(2)` and `O_(2)` gas under similar conditions their ratio of atoms is :-

Options

A. 1.5
B. 1.8
C. 0.085416666666667
D. 0.084027777777778

Answer

To find the ratio of atoms in flasks A and B containing CO₂ and O₂ gases, we can follow these steps:

### Step 1: Understand the composition of the gases
- Flask A contains CO₂, which has 1 carbon atom and 2 oxygen atoms per molecule.
- Flask B contains O₂, which has 2 oxygen atoms per molecule.

### Step 2: Determine the number of atoms in each gas
- For CO₂: Each molecule has a total of 3 atoms (1 carbon + 2 oxygen).
- For O₂: Each molecule has a total of 2 atoms (2 oxygen).

### Step 3: Establish the relationship between moles and atoms
- Since both flasks have equal capacity and are under similar conditions, we can assume they contain equal moles of gas. Let's denote the number of moles of CO₂ and O₂ as 'n'.

### Step 4: Calculate the total number of atoms in each flask
- Total atoms in flask A (CO₂):
\[ \text{Total atoms in CO₂} = n \times 3 = 3n \]
- Total atoms in flask B (O₂):
\[ \text{Total atoms in O₂} = n \times 2 = 2n \]

### Step 5: Find the ratio of the number of atoms
- The ratio of the number of atoms in flask A (CO₂) to flask B (O₂) is:
\[ \text{Ratio} = \frac{\text{Total atoms in CO₂}}{\text{Total atoms in O₂}} = \frac{3n}{2n} = \frac{3}{2} = 1.5 \]

### Conclusion
The ratio of the number of atoms in flask A (CO₂) to flask B (O₂) is 1.5.

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