The specific conductivity of a saturated solution of AgCl is `3.40xx10^(-6) Omega^(-1)cm^(-1)` at `25^(@)C`. If `lambda_(Ag)=62.3Omega^(-1)cm^(2)"mol"^(-1)` and `lambda_(Cl^(-))=67.7 Omega^(-1) cm^(2)"mol"^(-1)`, the solubility of AgCl at `25^(@)C` is :-
The specific conductivity of a saturated solution of AgCl is 3.40xx10^(-6) ohm^(-1) cm^(-1) at 25^(@)C . If lambda_(Ag^(+)=62.3 ohm^(-1) cm^(2) "mol"^(-1) and lambda_(Cl^(-))=67.7 ohm^(-1) cm^(2) "mol"^(-1) , the solubility of AgC at 25^(@)C is:
The conductivity of a saturated solution of a sparingly soluble salt MX_2 is found to be 4 xx 10^(-5) Omega^(-1) cm^(-1)." If "lambda_(m)^(oo) ( M^(2+))=50 Omega^(-1) cm^(2) mol^(-1) and lambda^(oo) (X^(-))= 50 Omega^(-1) cm^(2) mol^(-1) , the solubility product of the salt is about
If conductivity of water used to make saturated of AgCl is found to be 3.1xx10^(-5)Omega^(-1) cm^(-1) and conductance of the solution of AgCl=4.5xx10^(-5)Omega^(-1)cm^(-1) if lamda_(M)^(0)AgNO_(3)=200Omega^(-1)cm^(2) "mole"^(-1) lamda_(M)^(0)NaNO_(3)=310Omega^(-1)cm^(2) "mole"^(-1) calculate K_(SP) of AgCl
For a saturated solution of AgCl at 25^(@)C,k=3.4xx10^(-6) ohm^(-1)cm^(-1) and that of H_(2)O (l) used is 2.02xx10^(-6) ohm^(-1) cm^(-1),lambda_(m)^(@) for AgCl is 138 ohm^(-1) cm^(2) "mol"^(-1) then the solubility of AgCl in "mole"s per litre will be:
For a saturated solution of AgCl at 25^(@)C,k=3.4xx10^(-6)ohm^(-1)cm^(-1) and that of H_(2)O(l) used is 2.02xx10^(-6)ohm^(-1)cm^(-1). lambda_(m)^(@) for AgCl is 138ohm^(-1)cm^(2)mol^(-1) then the solubility of AgCl in moles per liter will be
The conductivity (k) of a saturated solution of AgBr at 298K is 8.5xx10^(-7)Scm^(-1) . If lambda^(@)._(Ag^(o+)) and lambda^(@)._(Br^(c-)) are 62 and 78 S cm^(2)mol^(-1) , respectively, then calculate the solubility and K_(sp) of AgBr .
The specific conductivity of a saturated solution of silver chloride is 2.30 xx 10^(-6) m ho cm^(-1) " at " 25^(@)C . Calculate the solubility of silver chloride at 25^(@)C " if " lamda_(Ag^(+)) = 61.9 m ho cm^(2) mol^(-1) and lamda_(Cl^(-)) = 76.3 m ho cm^(2) mol^(-1)
The specific conductivity of a saturated AgCl solution if found to be 2.12 xx 10^(-6)S cm^(-1) and that for water is 6 xx 10^(-8)S cm^(-1) . The solubility of AgCl is: (lambda_(eq)^(prop) = 103 S "equiv"^(-1) cm^(2))
Calculate the solubilty and solubility product of Co_(2) [Fe(CN)_(6)] is water at 25^(@)C from the following data: conductivity of a saturated solution of Co_(2)[Fe(CN)_(6)] is 2.06 xx 10^(-6) Omega^(-1) cm^(-1) and that of water used 4.1 xx 10^(-7) Omega^(-1) cm^(-1) . The ionic molar conductivites of Co^(2+) and Fe(CN)_(6)^(4-) are 86.0 Omega^(-1)cm^(-1) mol^(-1) and 44.0 Omega^(-1) cm^(-1) mol^(-1) .
Specific conductance of 0.1 M NaCl solution is 1.01xx10^(-2) ohm^(-1) cm^(-1) . Its molar conductance in ohm^(-1) cm^(2) mol^(-1) is
