1 gm metal carbonate requires 200 ml of 0.1N HCl for complete neutralization. What is the equivalent weight of metal carbonate:-

Options

A. 50
B. 40
C. 20
D. 100

Explanation

To find the equivalent weight of the metal carbonate, we can follow these steps:

### Step 1: Understand the neutralization reaction
In this problem, we have a metal carbonate that reacts with hydrochloric acid (HCl). The neutralization reaction involves the metal carbonate reacting with HCl to produce a salt, water, and carbon dioxide.

### Step 2: Write the formula for equivalents
The equivalent of a substance can be defined as:
\[ \text{Equivalent} = \frac{\text{Given weight}}{\text{Equivalent weight}} \]
For the metal carbonate, we can express this as:
\[ \text{Equivalent of metal carbonate} = \frac{1 \text{ gm}}{E} \]
where \(E\) is the equivalent weight of the metal carbonate.

### Step 3: Calculate the equivalents of HCl
The equivalents of HCl can be calculated using the formula:
\[ \text{Equivalent of HCl} = \text{Volume (L)} \times \text{Normality} \]
Given that the volume of HCl is 200 mL (which is 0.2 L) and the normality is 0.1 N, we can calculate:
\[ \text{Equivalent of HCl} = 0.2 \, \text{L} \times 0.1 \, \text{N} = 0.02 \, \text{equivalents} \]

### Step 4: Set up the equation
Since the equivalents of the metal carbonate will equal the equivalents of HCl at neutralization, we can set up the equation:
\[ \frac{1 \text{ gm}}{E} = 0.02 \]

### Step 5: Solve for equivalent weight \(E\)
Rearranging the equation gives:
\[ E = \frac{1 \text{ gm}}{0.02} = 50 \text{ gm/equiv} \]

### Conclusion
The equivalent weight of the metal carbonate is 50 g/equiv.