If uncertainty principle is applied to an object of mass 1 milligram, the uncertainty value of velocity and position will be
A
`10^(-4) m^(2)s^(-1)`
B
`10^(6)m^(2)s^(-1)`
C
`5xx10^(-29)m^(2)s^(-1)`
D
`10^(-34)m^(2)s^(-1)`
Text Solution
Verified by Experts
The correct Answer is:
C
`Deltax x mx Deltav=(h)/(4pi)` `Deltax Deltav=(h)/(2 pi xx m)=(6.62xx10^(-34))/(4xx3.14xx10^(-6))=5.44xx10^(-29)m^(2)s^(-1)`
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