Assertion:- H-COOH and `H-COOCH_(3)` are homologues. Reason:- Homologues differ by atleast one `CH_(2)` unit.
A
If both Assertion `&` Reason are True `&` the Reason is a correct explanation of the Assertion.
B
If both Assertion `&` Reason are True but Reason is not a correct explanation of the Assertion.
C
If Assertion is True but the Reason is False.
D
If Assertion is False but the Reason is True.
Text Solution
AI Generated Solution
The correct Answer is:
To solve the question, we need to analyze both the assertion and the reason provided.
### Step 1: Understand the Assertion
The assertion states that H-COOH (formic acid) and H-COOCH₃ (methyl formate) are homologues.
**Hint:** Recall the definition of homologues in organic chemistry.
### Step 2: Analyze the Compounds
- H-COOH is formic acid, which has the molecular formula CH₂O₂.
- H-COOCH₃ is methyl formate, which has the molecular formula C₂H₄O₂.
**Hint:** Compare the molecular formulas of the two compounds.
### Step 3: Determine the Difference
To be homologues, two compounds must differ by at least one CH₂ unit in their molecular formula.
- The difference in the number of carbon atoms between H-COOH and H-COOCH₃ is not just one CH₂ unit; they are different functional groups as well.
**Hint:** Identify the functional groups present in both compounds.
### Step 4: Identify Functional Groups
- H-COOH has a carboxylic acid functional group (-COOH).
- H-COOCH₃ has an ester functional group (-COOCH₃).
**Hint:** Recall that homologues must have the same functional group.
### Step 5: Conclusion on Assertion
Since H-COOH and H-COOCH₃ belong to different functional groups (carboxylic acid vs ester), they cannot be considered homologues. Therefore, the assertion is **false**.
### Step 6: Understand the Reason
The reason states that homologues differ by at least one CH₂ unit. This statement is **true**.
### Final Conclusion
- Assertion: **False** (H-COOH and H-COOCH₃ are not homologues).
- Reason: **True** (Homologues differ by at least one CH₂ unit).
### Final Answer
Assertion is false, but the reason is true.
---
Topper's Solved these Questions
TEST PAPERS
ALLEN|Exercise PAPER 1|60 Videos
TEST PAPERS
ALLEN|Exercise PAPER 2|58 Videos
TEST PAPER 4
ALLEN|Exercise CHEMISTRY|45 Videos
THERMODYNAMICS
ALLEN|Exercise EXERCISE -4|18 Videos
Similar Questions
Explore conceptually related problems
Justify that HCOOH and CH_3 COOH are homologues.
Assertion :- CH_(3)-O-C_(3)H_(7) and C_(2)H_(5)-O-C_(2)H_(5) are metamer. Reason:- They differ in alkyl group around polyvalent functional group.
Justify that C_2H_4 and C_3H_6 are homologues of one another.
CH_3COOC_2H_5 and C_2H_5COOCH_3 are related to each other as
Assertion : Butane and 2-methylbutane are homologues. Reason : Butane is a straight chain alkene while 2-methylbutane is a branched chain alkene.
(a) Write the structures of A and B in the following reactions : (i) CH_(3)COCl overset(H_2, Pd-BaSO_(4))(to)A overset(H_(2)N-OH)(to)B (ii) CH_(3)MgBr overset(1.CO_(2))underset(2.H_(3)O^+)(to)A overset(PCl_(5))(to)B (b) Distinguish between : (i) C_(6)H_(5)-COCH_(3) " and "C_(6)H_(5)-CHO (ii) CH_(3)COOH " and " HCOOH (c) Arrange the following in the increasing order of their boiling points : (i) CH_(3)CHO, CH_(3)COOH, CH_(3)CH_(2)OH
What is the formula of the next homologue of propene (C_3H_6) ?
The higer homologue of dimethylamine (CH_(3)-NH-CH_(3)) has the structure :-
Assertion :- In general, heat of neutralization of CH_(3)COOH by NaOH is less than heat of neutralization of H_(2)SO_(4) by NaOH . Reason :- H_(2)SO_(4) is a di basic acid while CH_(3)COOH is monobasic acid.
If 1 mole of CH_(3)COOH and 1 mole of C_(2)H_(5)OH are taken in 1 litre flask, 50% of CH_(3)COOH is converted into ester as, CH_(3)COOH_((l))+C_(2)H_(5)OH_((l))hArrCH_(3)COOC_(2)H_(5)(l)+H_(2)O_((l)) There is 33% conversion of CH_(3)COOH into ester, if CH_(3)COOH "and" C_(2)H_(5)OH have been taken initially in molar ratio x:1 , find x .