H(2)O(2)+2KIoverset(40% "yield")rarrI(2)...

`H_(2)O_(2)+2KIoverset(40% "yield")rarrI_(2)+2KOH`
`H_(2)O_(2)+2KMnO_(4)+3H_(2)SO_(4)overset(50% "yield")rarr K_(2)SO_(4)+2MnSO_(4)+3O_(2)+4H_(2)O`
150mL of `H_(2)O_(2)` sample was divided into two parts. First part was treated with KI and formed KOH required 200 mL of `M//2H_(2)SO_(4)` for neutralisation. Other part was treated with `KMnO_(4)` yielding 6.74 litre of `O_(2)` at 1 atm. and 273 K. Using % yield indicated find volume strength of `H_(2)O_(2)` sample used.

`5.04`

`33.6`

`3.36`

`11.2`

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H_2O_2+2KI rarr 40% yield I_2 + 2KOH H_2O_2+2KMnO_4+3H_2SO_4 rarr 50% yield K_2SO_4+2KMnSO_4+3O_2 +4H_2O 150mL of H_2 O_2 sample was divided into two parts. First part was treated with KI and formed KOH required 200mL of M/2H_2SO_4 for neutralisation. Other part was treated with KMnO_4 yielding 6.74 litre of O_2 at 1 atm. and 273K . Using % yield indicated find volume strength of H_2O_2 sample used.

MnO_(2)+2KOH+(1)/(2)O_(2) to K_(2)MnO_(4)+H_(2)O

MnO_(2)+2KOH+(1)/(2)O_(2) to K_(2)MnO_(4)+H(2)O

Mn(OH)_(2)+H_(2)SO_(4) to MnSO_(4)+2H_(2)O

CaSO_(3)darr+H_(2)SO_(4)toCaSO_(4)+SO_(2)uarr+H_(2)O

200 ml of 0.01 M KMnO_(4) oxidise 20 ml of H_(2)O_(2) sample in acidic medium. The volume strength of H_(2)O_(2) is

H_(4)underline(S_(2))O_(6)+H_(2)O to H_(2)SO_(3)+H_(2)SO_(4)

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