In system called the star system we have 1 star kilogram `=10^(20) kg`. 1 starmeter `=10^(8) m`, 1 starsecond `=10^(3)` second then calculate the value of 1 joule in this system.

Explanation

To calculate the value of 1 joule in the star system, we need to start with the definition of a joule in terms of its fundamental units.

1. **Understanding the definition of Joule**:
- The joule (J) is defined as the amount of energy transferred when a force of one newton is applied over a distance of one meter.
- In terms of fundamental units, 1 joule can be expressed as:
\[ 1 \text{ J} = 1 \text{ N} \cdot 1 \text{ m} = 1 \text{ kg} \cdot \text{m}^2/\text{s}^2 \]
- Therefore, the dimensional formula for joule is:
\[ [J] = [M][L^2][T^{-2}] \]

2. **Convert the units to the star system**:
- In the star system, we have:
- 1 star kilogram (star kg) = \(10^{20}\) kg
- 1 star meter (star m) = \(10^{8}\) m
- 1 star second (star s) = \(10^{3}\) s

3. **Substituting the values into the joule formula**:
- We can substitute the values for mass, length, and time from the star system into the joule formula:
\[ 1 \text{ J} = (1 \text{ star kg}) \cdot (1 \text{ star m})^2 / (1 \text{ star s})^2 \]
- Substituting the star units:
\[ 1 \text{ J} = (10^{20} \text{ kg}) \cdot (10^{8} \text{ m})^2 / (10^{3} \text{ s})^2 \]

4. **Calculating the values**:
- Calculate \((10^{8} \text{ m})^2\):
\[ (10^{8})^2 = 10^{16} \text{ m}^2 \]
- Calculate \((10^{3} \text{ s})^2\):
\[ (10^{3})^2 = 10^{6} \text{ s}^2 \]
- Now substitute these back into the equation:
\[ 1 \text{ J} = (10^{20}) \cdot (10^{16}) / (10^{6}) \]

5. **Simplifying the expression**:
- Combine the powers of ten:
\[ 1 \text{ J} = \frac{10^{20} \cdot 10^{16}}{10^{6}} = 10^{20 + 16 - 6} = 10^{30} \text{ star J} \]

Thus, the value of 1 joule in the star system is:
\[ \boxed{10^{30} \text{ star joules}} \]