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The charge per unit length of the four q...

The charge per unit length of the four quadrant of the ring is `2 lambda, -2lambda, lambda` and `-lambda` respectively. The electric field at the centre is:

A

`(-lambda)/(2piepsilon_(0)R)hat(i)`

B

`lambda/(2pi epsilon_(0)R) hat(j)`

C

`(sqrt(2)lambda)/(4 pi epsilon_(0)R) hat(i)`

D

None

Text Solution

Verified by Experts

The correct Answer is:
A
`E_("net")=sqrt(2)E=sqrt(2)[(lambdasqrt(2))/(4pi in_(0)R)]rArr vec(E)=(lambda(-hat(i)))/(2pi in_(0)R)`
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