If a liquid takes `30` seconds in cooling of `80^(@)C` to ` 70^(@)C` and `70` seconds in cooling `60^(@)C` to `50^(@)C`, then find the room temperature.

Explanation

To solve the problem of finding the room temperature given the cooling times of a liquid, we can use Newton's Law of Cooling. The law states that the rate of change of temperature of an object is proportional to the difference between its own temperature and the ambient temperature (room temperature).

Let's denote:
- \( \theta_1 \) = initial temperature of the liquid
- \( \theta_2 \) = final temperature of the liquid
- \( \theta_0 \) = room temperature
- \( T \) = time taken for cooling
- \( K \) = cooling constant
...