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Steam at 100^(@)C is passed into 1.1 kg ...

Steam at `100^(@)C` is passed into `1.1 kg` of water contained in a calorimeter of water equivalent `0.02kg` at `15^(@)C` till the temperature of the calorimeter and its content rises to `80^(@)C`. What is the mass of steam condensed? Latent heat of steam = `536 cal//g`.

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To solve the problem, we will follow these steps: ### Step 1: Identify the known values - Mass of water (m1) = 1.1 kg - Water equivalent of calorimeter (m2) = 0.02 kg - Initial temperature of water and calorimeter (T_initial) = 15°C - Final temperature (T_final) = 80°C - Latent heat of steam (L) = 536 cal/g ...
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