Home
Class 12
PHYSICS
The mass of hydrogen molecule is 3.32xx1...

The mass of hydrogen molecule is `3.32xx10^(-27)` kg. If `10^(23)` hydrogen molecules strikes per second at 2 `cm^(2)` area of a rigid wall at an angle of `45^(@)` from the normal and rebound back with a speed of 1000 `ms^(-1)`, then the pressure exerted on the wall is

Text Solution

Verified by Experts

As the impact is elastic ` therefore |vec(p)_(1)| = |vec(p)_(2)|`= p= mv = `3.32xx10^(-24) kg m//s`
The change in momentum along the normal `Deltap= |vec(p)_(2) - vec(p)_(1)| = 2p "cos"45^(@) = sqrt(2)p`
If f is the collision frequency then force applied on the wall `F= (Deltap)/(Deltat) = Deltap xx f = sqrt(2)pf`
` therefore Pressure P=F/A = (sqrt(2)pf)/(A) = (sqrt(2) xx 3.32 xx 10^(-24) xx 10^(23))/(2xx10^(-4)) = 2.347xx10^(3)N//m^(2)`
Promotional Banner

Topper's Solved these Questions

  • GEOMETRICAL OPTICS

    ALLEN|Exercise SOME WORKED OUT EXAMPLES|83 Videos

  • GEOMETRICAL OPTICS

    ALLEN|Exercise EXERCISE -01|65 Videos

  • CURRENT ELECTRICITY

    ALLEN|Exercise EX.II|66 Videos

  • GRAVITATION

    ALLEN|Exercise EXERCISE 4|9 Videos

Similar Questions

Explore conceptually related problems

The mass of a molecule of hydrogen is 3.332xx10^(-27) kg. Find the mass of 1 kg mol of hydrogen gas.

Water from a hosepipe of radius 5 cm strikes a wall at a speed of 5ms^(-1) normally and stops. The force exerted on the wall in newton is

A body of mass 2kg collides with a wall with speed 100 m/s and rebounds with same speed. If the time of contact was 1/50 second, the force exerted on the wall is

A body of mass 3kg moving with speed 5 ms^(-1) , hits a wall at an angle of 60^(@) and return at the same angle. The impact time was 0.2 sec. calculate the force exerted on the wall :

A jet of water with cross section of 6 cm^(2) strikes a wall at an angle of 60^(@) to the normal and rebounds elastically from the wall without losing energy. If the velocity of the water in the jet is 12 m//s , the force acting on the wall is

A horizontal jet of water coming out of a pipe of area of cross - section 20 cm^(2) hits a vertical wall with a velocity of 10 ms^(-1) and rebounds with the same speed. The force exerted by water on the wall is,

If 10^(22) gas molecules each of mass 10^(-26)kg collide with a surface (perpendicular to it) elastically per second over an area 1m^(2) with a speed 10^(2)m//s , the pressure exerted by the gas molecules will be of the order of :

A body of mass 3 kg moving with velocity 10 m/s hits a wall at an angle of 60^(@) and returns at the same angle. The impact time was 0.2 s. Calculate the force exerted on the wall.

A hose pipe lying on the ground shoots a stream of water upward at an angle 60^@ to the horizontal at a speed of 20 ms^(-1) . The water strikes a wall 20m away at a height of (g=10ms^2)

A ball of mass 600 gm strikes a wall with a velocity of 5 ms^(-1) at an angle 30^@ with the wall and rebounds with the same speed at the same angle with the wall. The change in momentum of the ball is, (in kg ms^(-1) )