Calculate the number of degrees of freedom of molecules of hydrogen in 1cc of hydrogen gas at NTP.

Explanation

`22400 cm^(3)` of every gas constains ` 6.02 xx 10^(23)` molecules.
` therefore` Number of molecules in `1 cm^(3)` of gas =`(6.02xx10^(23))/22400 = 0.26875xx10^(20)`
Number of degrees of freedom of a `H_(2)` gas molecule = `5`
`therefore` Total number of degrees of freedom of `0.26875 xx 10^(20) xx 5 = 1.34375 xx 10^(20)`.