At normal pressure and `0^(@)C` temperature the volume of `1` kg of ice is reduced by `91 cm^(3)` on melting . Laters heat of melting of ice is `3.4xx 10^(5)J//kg`. Calculate the changes in the internal energy when `2`kg of ice melts normal pressure and `0^(@)C. (P=1.01 xx 10^(5) Nm^(-2))`

Explanation

To calculate the change in internal energy when 2 kg of ice melts at normal pressure and 0°C, we can follow these steps:

### Step 1: Calculate the heat absorbed during melting
The heat absorbed (Q) during the melting of ice can be calculated using the formula:
\[ Q = L_f \times m \]
where:
- \( L_f \) is the latent heat of fusion of ice, which is given as \( 3.4 \times 10^5 \, \text{J/kg} \)
- \( m \) is the mass of ice, which is \( 2 \, \text{kg} \)
...