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A body cools in a surrounding of consta...

A body cools in a surrounding of constant temperature `30^(@)C`. Its heat capacity is `2J//^(@)C`. Initial temperature of the body is `40^(@)C`. Assume Newton's law of cooling is valid. The body cools to `36^(@)C` in `10` minutes.
In further `10` minutes it will cool from `36^(@)C` to :

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
D
`( dtheta)/(dt) = (-kA)/("ms") (T-T_(0))` magnitude of slope will decrease with time.
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