An ideal gas in enclosed in a tube and is held in the vertical position with the closed end upward. The length of pellet of mercury entrapping the gas is `h = 10` cm and the length of the tube occupied by gas is `l=40` cm. Calculate the length occupied by the gas when it is turned through `theta= 60^(@)` and `90^(@)`. Atmospheric pressure , `H= 76` cm of mercury.

Answer

`37.2 cm , 34.7cm`

Explanation

For gas trapped in the tube `P_(1)V_(1) = P_(2)V_(2) = P_(3)V_(3)`
`implies (76-h)Al = (76-"hcos"60^(@)) Al = 76 xx Al`
`implies 66 xx 40 = 71 xx l' = 76 xx l'' l = 37.2 "cm"` & `l'=34.7"cm"`