One mole of an ideal gas is heated isobarically from the freezing point to the boiling point of water, each under normal pressure. Find out the work done by the gas and the change in its internal energy. The amount of heat involved is 1 kJ. Given gas constant R= 8.3 J/mol K.

Answer

`830J , 170J`

Explanation

`DeltaU = nC_(V)DeltaT , Q = nC_(P)DeltaT "and" W = nRDeltaT = (1)((25)/(3)) (100) = (2500)/(3) J`
`DeltaU = n(C_(P) -R)DeltaT = nC_(P)DeltaT - nRDeltaT`
=`1000-(1) ((25)/(3)) (100)= (500)/(3)J`