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Optic axis of a thin equiconvex lens is the x-axis. The co-rodinates of a point object and its image axis `(-40 cm, 1 cm)` and `(50 cm, -2 cm)` respectively. Lens is located at

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The correct Answer is:
C

`m = (-2)/(1) = -2 = (v)/(u) implies |v| = |2u|`
`(90-u) = 2u implies u = 30 "cm"`

Hence lens location = -40 + 30 =-10 cm
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ALLEN-GEOMETRICAL OPTICS-EXERCISE- 01
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