Home
Class 12
PHYSICS
Consider the following diagram represent...

Consider the following diagram representing magnitude of magnification against image distance for a convex lens:

`{:("Column I","Column II"),((A)"Focal length of the lens",(p)"Inverse of slope of line"),((B)"Intercept on x- axis",(q) "Unity"),((C)"Intercept on y-axis" , (r) "Focal length") , ((D) "Magnitude of slope of the line(s)", (s) "Inverse of the focal length"):}`

Text Solution

Verified by Experts

The correct Answer is:
(A)-p (B)-r (C)-q (D)-s

`m= (v-f)/(f) = (v)/(f) - 1 (therefore y = mx+c`)
m = slope = `(1)/(f)` (magnitude of slope of line)
Intercet on y axis c =-1 (unity)
Intercet on x-axis `implies m =0`
`implies 0 = (v)/(f) -1 implies v = f `(focal length)
Promotional Banner

Topper's Solved these Questions

  • GEOMETRICAL OPTICS

    ALLEN|Exercise EXERCISE-04[A]|23 Videos
  • GEOMETRICAL OPTICS

    ALLEN|Exercise EXERCISE-04[B]|18 Videos
  • GEOMETRICAL OPTICS

    ALLEN|Exercise EXERCISE-2|44 Videos
  • CURRENT ELECTRICITY

    ALLEN|Exercise EX.II|66 Videos
  • GRAVITATION

    ALLEN|Exercise EXERCISE 4|9 Videos

Similar Questions

Explore conceptually related problems

Column - II shows the optical phenomenon that can be associated with optical components given in column- I . Note the column - I may have more than one matching options in column-II. {:("Column I","Column II"),((A)"Convex mirror",(p)"Dispersion"),((B)"Converging lens",(q) "Deviation"),((C)"Thin prism" , (r) "Real image of real object") , ((D) "Glass slab", (s) "Virtual images of real object"):}

Match the column I with column II {:("Column-I","Column-II"),((A)"Fructose",(p)"Protein"),((B)"Zwitterion",(q)"Inversion"),((C )"Peptide linkage",(r)alpha-"Amino acid"),((D)"Hydrlysis of cane sugar",(s)"Carbohydroate"),(,(t)"Ketose"):}

Match the following columns. |{:(,"Column I",,"Column II"),((A),"d v/dt",(p),"Acceleration"),((B),"d|v|/dt",(q),"Magnitude of acceleration"),((C ),(dr)/(dt),(r ),"Velocity"),((D),|(dr)/(dt)|,(s),"Magnitude of velocity"),(,,(t),"Rate of change of speed"):}|

The graph in Fig. shows how the inverse of magnification 1//m produced by a convex thin lens varies with object distance u . What was the focal length of the lens used ? .

When an object is at distances x and y from a lens, a real image and a virtual image is formed respectively having same magnification. The focal length of the lens is

An object is at a distance of 20 m form a convex lens of focal length 0.3m The lens forms an image of the object moves away form the lens at a speed of 5m//s the speed and direction of the image will be :

Draw ray diagrams showing the image formation by a convex lens when an object is placed (a) between optical centre and focus of the lens (b) between focus and twice the focal length of the lens ( c) at twice the focal length of the lens (d) at infinity , (e) at the focus of the lens

(i) A diverging lens of focal length 15 cm, forms an image at distance of 10 cm from the lens. How far is the object placed from the lens ? (ii) What is the linear magnification of the image?

Column I (optical system ) Column II (focal length ) (P) 80 "cm" " " (Q) 40 "cm" " " (R) 30"cm" " " (S) 20"cm"

{:("Column I","Column II"),((A)" An object is placed at a distance equal to focal length from pole before convex mirror",(p)" Magnification is "(infty)),((B)" An object is placed at focus before a concave mirror",(q)" Magnification is (0.5)"),((C) "An object is placed at the centre of curvature before a concave mirror" , (r) "Magnification is (1//3)") , ((D) " An object is placed at a distance equal to radius of curvature before a convex mirror" , (s) "Magnification is (-1)"):}