In Figure ., L is a converging lens of focal length 10cm and M Iis a concave mirror of radius of curvature 20cm. A point object O is placed in front of the lens at a distance of 15cm. Ab and CD are optical axes of the lens and mirror, respectively. Find the distance of the final image formed by this system from the optical center of the lens. The distance between CD and AB is 1cm.

Answer

(-15 cm , -6mm)

Explanation

Image formed by the lens `v= (-15 xx10)/(-15 + 10) = 30`
(Right from lens)
Reflection from mirror u = -15
`v = (-15 xx 10)/(-15 + 10) = -30 , m = ((-30))/(-15) = -2`
Co-ordinate of image = `(30, 0.3 cm)`
Now again taking refraction from lens )
`v= (-15 xx 10)/(-15 + 10) = 30` (left from lens) m= `(30)/(-15) = -2`
`therefore` Final co-ordinate of image = (-15 cm, - 6mn)