Time period of a back performing `SHM` is `2` second and it can travel to and fro from equilibrium position upto maximum `5cm`. At start the pendulum is at maximum displacement on right side of equilibrium position. Find displacement and time relation.
Text Solution
AI Generated Solution
To find the displacement and time relation for a pendulum performing Simple Harmonic Motion (SHM), we can follow these steps:
### Step 1: Identify the parameters
- Given time period \( T = 2 \) seconds.
- Maximum displacement (amplitude) \( A = 5 \) cm.
### Step 2: Calculate angular frequency \( \omega \)
The angular frequency \( \omega \) is related to the time period \( T \) by the formula:
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