The velocity of a particle in `S.H.M.` at positions `x_(1)` and `x_2` are `v_(1)` and `v_(2)` respectively. Determine value of time period and amplitude.
Text Solution
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To solve the problem, we need to determine the time period (T) and amplitude (A) of a particle in Simple Harmonic Motion (SHM) given its velocities (v1 and v2) at two different positions (x1 and x2).
### Step-by-Step Solution:
1. **Understanding the Velocity in SHM**:
The velocity (v) of a particle in SHM can be expressed as:
\[
v = \omega \sqrt{A^2 - x^2}
...
A particle is executing SHM along a straight line. Its velocities at distances x_(1) and x_(2) from the mean position are v_(1) and v_(2) , respectively. Its time period is
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Two cars of same mass are moving with velocities v_(1) and v_(2) respectively. If they are stopped by supplying same breaking power in time t_(1) and t_(2) respectively then (v_(1))/(v_(2)) is
