Home
Class 12
PHYSICS
The angle made by the string of a simple...

The angle made by the string of a simple pendulum with the vertical depends on time as `theta=pi/90sin[(pis^-1)t]`. Find the length of the pendulum if `g=pi^2ms^-2`

A

1

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
A
Here `2pisqrt((m)/(k)) = (2pi)/(omega) = (2pi)/(pi) = 2pisqrt((l)/(g)) rArr (l)/(g) = (1)/(pi^(2))` But `g = pi^(2)` therefore `l = 1 m`
Promotional Banner

Topper's Solved these Questions

  • SIMPLE HARMONIC MOTION

    ALLEN|Exercise SOME WORKED OUT EXAMPLES|29 Videos

  • SIMPLE HARMONIC MOTION

    ALLEN|Exercise Exercise-01|117 Videos

  • RACE

    ALLEN|Exercise Basic Maths (Wave Motion & Dopplers Effect) (Stationary waves & doppler effect, beats)|24 Videos

  • TEST PAPER

    ALLEN|Exercise PHYSICS|4 Videos

Similar Questions

Explore conceptually related problems

If the length of a simple pendulum is increased by 2%, then the time period

The length of a simple pendulum is made one-fourth. Its time period becomes :

State how does the time period of a simple pendulum depend on length of pendulum.

Derive an expression for the time period (T) of a simple pendulum which may depend upon the mass (m) of the bob, length (l) of the pendulum and acceleration due to gravity (g).

Figure shown the kinetic energy K of a pendulum versus. its angle theta from the vertical. The pendulum bob has mass 0.2kg The length of the pendulum is equal to (g = 10m//s^(2)) ,

Find the length of seconds pendulum at a place where g =4 pi^(2) m//s^(2) .

Find the length of seconds pendulum at a place where g = pi^(2) m//s^(2) .

A simple pendulum is suspended from the ceiling of a car taking a turn of radius 10 m at a speed of 36 km/h. Find the angle made by the string of the pendulum with the vertical if this angle does not change during the turn. Take g=10 m/s^2 .

Fig. show a conical pendulum. If the length of the pendulum is l , mass of die bob is m and theta is the angle made by the string with the vertical show that the angular momentum of the pendulum about the point of support is: L = sqrt((m^(2)gl^(3) sin^(4)theta)/(cos theta))

Show that the angle made by the string with the vertical in a conical pendulum is given by costheta=(g)/(Lomega^(2)) , where L is the string and omega is the angular speed.