A block of mss `m` is placed on a level frictionless table. The block is attached to a horizontally aligned spring fixed with its other end and is vibrating in a horizontal with the pariod `T`. Suddenly at the instant of time when the spring comes to the position of euilibrium and becomes unstretched the block disconnects form the spring and continues sliding across the frictionless surface away from the until it encounters loop of radius `R`. What must be the amplitude of vibrations of the block s on the spring in order for the block to complets one loop without falling down?

Options

A. `A ge (T)/(2pi)sqrt(5gR)`
B. `A le (T)/(2pi)sqrt(5gR)`
C. `A ge T/pisqrt(5gR)`
D. `A le T/(2pi)sqrt(5gR)`

Answer

A