A particle of mass 0.1 kg is executing SHM of amplitude 0.1 m . When the particle passes through the mean position , its KE is `8 xx 10^(-3)` J. Find the equation of motion of the particle if the initial phase of oscillation is `45^(@)`

Answer

A, D

Explanation

`1/2 mv_(max)^(2) = 8 xx 10^(-3)`
`rArr 1/8 momega^(2)a^(2) = 8 xx 10^(-3)`
`rArr omega = 4rad//s`
Therefore equation of SHM
`x = 0.1 sin (4t + (pi)/(4))`