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The maximum kinetic energy of photoelect...

The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4 eV. The stopping potential in volts is

A

2

B

4

C

6

D

10

Text Solution

Verified by Experts

The correct Answer is:
B
`K_("max") = hv - phi rArr V_(s) = (K_(max))/(e) = (4eV)/(e) = 4` volts
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ALLEN-SIMPLE HARMONIC MOTION-Exercise-01
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